answer Home › Forums › density functional theory › functions and functionals › answer This topic has 0 replies, 1 voice, and was last updated 5 days, 17 hours ago by stephen wienk. Viewing 1 post (of 1 total) Author Posts October 3, 2026 at 12:06 pm #15178 stephen wienkParticipant a definite integral, because you start from a function and end up with a value. Author Posts Viewing 1 post (of 1 total) You must be logged in to reply to this topic. Log In Username: Password: Keep me signed in Log In
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